2y^2+4y+3-x=0

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Solution for 2y^2+4y+3-x=0 equation:


Simplifying
2y2 + 4y + 3 + -1x = 0

Reorder the terms:
3 + -1x + 4y + 2y2 = 0

Solving
3 + -1x + 4y + 2y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -1x + 4y + -3 + 2y2 = 0 + -3

Reorder the terms:
3 + -3 + -1x + 4y + 2y2 = 0 + -3

Combine like terms: 3 + -3 = 0
0 + -1x + 4y + 2y2 = 0 + -3
-1x + 4y + 2y2 = 0 + -3

Combine like terms: 0 + -3 = -3
-1x + 4y + 2y2 = -3

Add '-4y' to each side of the equation.
-1x + 4y + -4y + 2y2 = -3 + -4y

Combine like terms: 4y + -4y = 0
-1x + 0 + 2y2 = -3 + -4y
-1x + 2y2 = -3 + -4y

Add '-2y2' to each side of the equation.
-1x + 2y2 + -2y2 = -3 + -4y + -2y2

Combine like terms: 2y2 + -2y2 = 0
-1x + 0 = -3 + -4y + -2y2
-1x = -3 + -4y + -2y2

Divide each side by '-1'.
x = 3 + 4y + 2y2

Simplifying
x = 3 + 4y + 2y2

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